Geometric Series Convergence Checker

Enter the first term and common ratio to check whether the geometric series converges.

How it is calculated

The series is a + ar + ar² + ar³ + …, with first term a and common ratio r. The tool first reports |r| to six decimals. The series converges when |r| < 1, and then the sum is S = a / (1 − r). When it does not converge, the sum column shows what happens: for r ≥ 1 it shows ∞ if a is positive and −∞ if a is negative, and for r ≤ −1 it shows "diverges", because the partial sums swing back and forth (r = −1) or grow in alternating signs. A first term of 0 always counts as convergent with sum 0, whatever r is. Enter r as a plain decimal such as 0.5 or −0.5; fractions like 1/2 and percent signs are not accepted. Results are rounded to six decimals.

Worked example

Take a = 8 and r = −0.5, so the terms are 8, −4, 2, −1, 0.5, … The absolute ratio is 0.500000, which is below 1, so the checker reports that the series converges (it shows Yes for "Converges?"). The sum is 8 / (1 − (−0.5)) = 8 / 1.5 = 5.333333. The partial sums 8, 4, 6, 5, 5.5 … alternate around that value and get closer to it.

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Common mistakes

  • Typing the ratio as a fraction (1/2) or a percentage (50%). The field takes a decimal such as 0.5; text like these returns no result.
  • Using the ratio between the first two terms of a series that is not geometric. The formula only applies when every term is the previous one multiplied by the same r, so check the third term too.
  • Mixing up r with 1 − r. The sum is a divided by (1 − r), so for r = 0.9 the sum is ten times the first term, not close to a.
  • Entering a negative ratio as its absolute value. With r = −0.5 the sum is 5.333333, while r = 0.5 gives 16.000000; the sign matters for the sum, though not for convergence.
  • Reading the ∞ or "diverges" output as an error. For |r| = 1 or more the series really has no finite sum, and r = −1 never settles on one value.

About this calculator

An infinite geometric series a + ar + ar² + ar³ + … converges to a finite sum only when the common ratio satisfies |r| < 1; in that case the sum equals a ÷ (1 − r). If |r| ≥ 1, the terms don't shrink fast enough (or grow), and the series diverges to infinity or oscillates without settling on a value.

This checker takes the first term and common ratio, tests the |r| < 1 condition, and returns the exact sum when convergence holds. Calculus and pre-calculus students use it to check series-convergence homework, while it also mirrors real applications such as computing the present value of a perpetuity in finance, the total distance in a bouncing-ball or Zeno's-paradox problem, or the steady-state gain of a feedback loop in engineering — all of which reduce to the same a ÷ (1 − r) formula.

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